What We Are Learn On This Post
GlobalLogic interview Questions: The most important part of preparing for an interview is practice. Knowing what job interview questions you might be asked is essential – that way, you can craft your answers well in advance, and feel confident in your responses when the pressure is on.
Wouldn’t it be great if you knew exactly what interview questions are asked for the Test Engineer, QA for Manual & Automation Positions, We can’t read minds, unfortunately, but we’ll give you the next best thing: a list of previously asked GlobalLogic interview questions and answers.
| Post On: | GlobalLogic Interview Questions |
| Post Type: | Interview Questions |
| Published On: | www.softwaretestingo.com |
| Applicable For: | Freshers & Experience |
| Get Updates: | Software Testingo Telegram Group |
We have tried to share some of the manual testing interview questions, selenium interview questions & testing interview questions also, but we are recommending spending some quality time to get comfortable with what might be asked when you go for the GlobalLogic interview.
Still, we need you are love and support to make this platform more helpful to our fellow testers. So it would be great if you will share your recent interview questions and experience with us. You Can share those details by connecting us at softwaretestingo.com@gmail.com.
GlobalLogic Interview Questions
- String s = “ABC “, Output should be -ABC ACB BAC BCA CBA CAB
package com.SoftwareTestingo.InterviewPrograms;
public class Abc
{
public static void main(String[] args)
{
String s ="ABC";
String temp = s;
String concat = "";
String reverse = "";
System.out.print(temp);
for (int i = 1; i <= 5; i++)
{
if (i % 2 != 0) {
String[] characters = new String[temp.length()];
for (int index = 0; index < temp.length(); index++)
{
characters[index] = String.valueOf(temp.charAt(index));
}
String prefix = temp.substring(0, temp.length()-2);
concat = prefix + characters[temp.length()-1] + characters[temp.length()-2];
System.out.print(" " + concat);
}
if (i % 2 == 0 && i != 2)
{
String[] characters = new String[temp.length()];
for (int index = 0; index < temp.length(); index++)
{
characters[index] = String.valueOf(temp.charAt(index));
}
String suffix = temp.substring(temp.length()-1);
concat = characters[1] + characters[0] + suffix;
System.out.print(" " + concat);
}
if (i == 2)
{
String[] characters = new String[temp.length()];
for (int index = 0; index < temp.length(); index++)
{
reverse = temp.charAt(index) + reverse;
characters[index] = String.valueOf(temp.charAt(index));
}
for (int index = 0; index < reverse.length(); index++)
{
characters[index] = String.valueOf(reverse.charAt(index));
}
String prefix = reverse.substring(0, reverse.length()-2);
concat = prefix + characters[reverse.length()-1] + characters[reverse.length()-2];
System.out.print(" " + concat);
}
temp = concat;
}
}
}
We Thank Sivaprasad Rajasekaran for coming forward and sharing the solutions for the above Java programs. We hope this motivates others also to share their interview experience and interview questions.
Still, we need your Love ❤️ & support 🤝 to build a better platform for our fellow Testing Community to make such an incredible platform where a QA can get the real-time testing interview questions in a single place.
- String S = “my name is Ramesh”, I should get 2 output
1 Ramesh
2 Is should be constant and other words should change
For example my name is Ramesh. - String s = “123” & Int I = 123, How do you compare the value ?
Ans: Thanks Kopal For the solution
package com.SoftwareTestingo.InterviewPrograms;
public class ConvertInttoSting
{
public static void main(String[] args)
{
String str = "123";
int i = 123;
if (i == (Integer.valueOf(str)))
{
System.out.println("Both values are same");
}
else
System.out.println("Both values are not same");
}
}
- String s= “selenium” & String s = new string (selenium) How to compare the values. ?
- If there is a drop-down of the month, we should print the 2nd, 4rth, 6th, or 8th ??
- What is the use of before suite, before class, before method, where you have used in your project?
- In which annotations we call the initialization.. if we call from beforemethod, each and every time, browser Wil is launched and it enters the username and password…if we have 100 test cases in that file, the execution time will be more.. how to solve this issue.
- If your HTML dom is changing dynamically. How will you run your test cases and how to solve this issue? If anyone is aware of the answer please provide it?
- I am not posting these questions for “getting likes there are many people trying for a job”. This kind of question will be useful for that people..so please don’t like this. if you know the answer, then mention it in the comments, or else please ignore it.
GlobalLogic F2F Interview Questions
- What are the differences between abstract class and interface in java?
- When do we use an interface either than an abstract class?
//Program to compare String and int
public class ConvertInttoSting {
public static void main(String[] args) {
String str = “123”;
int i = 1273;
if (i == (Integer.valueOf(str))) {
System.out.println(“Both values are same”);
} else
System.out.println(“Both values are not same”);
}
}
If the DOM is changing Dynamically you can use Explicit wait and Expected Conditions also still you are having issues you can go with Fluent Wait also for element capture do use xpath functions like contains, starts-with or cssSelector with id or some relevant which will help you capture the element properly.
In which annotations we call the initialization: – for this we can use BeforClass for initialization
// Program for String s = “ABC “, Output should be -ABC ACB BAC BCA CBA CAB
public class Practice {
public static void main(String[] args) {
String s = “ABC”;
printstringper(s, “”);
}
static void printstringper(String str, String per) {
if (str.length() == 0) {
System.out.print(per + ” “);
return;
}
for (int i = 0; i < str.length(); i++) {
char ch = str.charAt(i);
String ros = str.substring(0, i) + str.substring(i + 1);
printstringper(ros, per + ch);
}
}
}
class HelloWorld {
public static void main(String[] args) {
String s =”Selenium”;
String s1 = new String (“Selenium”);
if(s==s1){ // False
System.out.println(“True”);
}
else{
System.out.println(“False”);
}
s1=s1.intern();
if(s==s1){ // True
System.out.println(“True”);
}
else{
System.out.println(“False”);
}
}
}
public class ABC {
public static void main(String[] args) {
String s = “ABC”;
String temp = s;
String concat = “”;
String reverse = “”;
System.out.print(temp);
for (int i = 1; i <= 5; i++) {
if (i % 2 != 0) {
String[] characters = new String[temp.length()];
for (int index = 0; index < temp.length(); index++) {
characters[index] = String.valueOf(temp.charAt(index));
}
String prefix = temp.substring(0, temp.length() – 2);
concat = prefix + characters[temp.length() – 1] + characters[temp.length() – 2];
System.out.print(" " + concat);
}
if (i % 2 == 0 && i != 2) {
String[] characters = new String[temp.length()];
for (int index = 0; index < temp.length(); index++) {
characters[index] = String.valueOf(temp.charAt(index));
}
String suffix = temp.substring(temp.length() – 1);
concat = characters[1] + characters[0] + suffix;
System.out.print(" " + concat);
}
if (i == 2) {
String[] characters = new String[temp.length()];
for (int index = 0; index < temp.length(); index++) {
reverse = temp.charAt(index) + reverse;
characters[index] = String.valueOf(temp.charAt(index));
}
for (int index = 0; index < reverse.length(); index++) {
characters[index] = String.valueOf(reverse.charAt(index));
}
String prefix = reverse.substring(0, reverse.length() – 2);
concat = prefix + characters[reverse.length() – 1] + characters[reverse.length() – 2];
System.out.print(" " + concat);
}
temp = concat;
}
}
}