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SoftwareTestingo » Java Programs » How to Find That A Number Is Armstrong Numbers In Java?

How to Find That A Number Is Armstrong Numbers In Java?

Last Updated on: April 23, 2019 By Softwaretestingo Editorial Board

What We Are Learn On This Post

  • Check Also: Handle Exception Using Try and Finally In Java

Armstrong Numbers Find In Java: How to Find That A Number Is Armstrong Numbers In Java?

package com.softwaretestingblog.programs;
import java.util.Scanner;
public class ArmStrongNumbers {
   public static void main(String[] args) {
      // TODO Auto-generated method stub
      Scanner in=new Scanner(System.in);
      System.out.println("Enter the number");
      int a,c=0,num,temp;
      num=in.nextInt();
      temp=num;
      while(num>0)
      {
         a=num%10;
         num=num/10;
         c=c+(a*a*a);
      }
      if(temp==c)
         System.out.println(temp+ " Armstrong number");   
      else  
         System.out.println(temp+" Not Armstrong number"); 
   }
}

Check Also: Handle Exception Using Try and Finally In Java

Output:

Enter the number: 371
371 Armstrong number

 

    Filed Under: Java Programs Tagged With: Java Programs Basics, Java Programs For Interview, Java Programs PDF, Java Programs to Practice

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