How to Find That A Number Is Armstrong Numbers In Java?

Armstrong Numbers Find In Java: How to Find That A Number Is Armstrong Numbers In Java?

package com.softwaretestingblog.programs;
import java.util.Scanner;
public class ArmStrongNumbers {
   public static void main(String[] args) {
      // TODO Auto-generated method stub
      Scanner in=new Scanner(System.in);
      System.out.println("Enter the number");
      int a,c=0,num,temp;
      num=in.nextInt();
      temp=num;
      while(num>0)
      {
         a=num%10;
         num=num/10;
         c=c+(a*a*a);
      }
      if(temp==c)
         System.out.println(temp+ " Armstrong number");   
      else  
         System.out.println(temp+" Not Armstrong number"); 
   }
}

Output:

Enter the number: 371
371 Armstrong number